ft_strpbrk

This solution has been proposed by Duc Nguyen (Find his Github link here )

Subject

Assignment name	: ft_strpbrk
Expected files	: ft_strpbrk.c
Allowed functions: None
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Reproduce exactly the behavior of the function strpbrk
(man strpbrk).

The function should be prototyped as follows:

char	*ft_strpbrk(const char *s1, const char *s2);

Man page

STRPBRK(3) (simplified)

NAME
     strpbrk –- locate multiple characters in string
LIBRARY
     Standard C Library (libc, -lc)
SYNOPSIS
     #include <string.h>
     char *strpbrk(const char *s, const char *charset);

DESCRIPTION
     The strpbrk() function locates in the null-terminated string s the first
     occurrence of any character in the string charset and returns a pointer to this
     character.  If no characters from charset occur anywhere in s strpbrk()
     returns NULL.
RETURN VALUES
     The strpbrk() function return a pointer to the first occurence of any character
     in the string,if no characters occur anywhere in s, strpbrk() returns NULL.

Commented solution

ft_strpbrk()

char *ft_strpbrk(const char *s1, const char *s2)
{
    int i = 0;
    int j = 0;
    char *re = (char *)s1;

    while (s1[i])
    {
        j = 0;
        while (s2[j])
        {
            if (s1[i] == s2[j])
                return re;
            j++;
        }
        i++;
        re++;
    }
    return NULL;
}

Explanation of char *re = (char *)s1;

In this function, the variable re is a temporary pointer that is initially set to the start of the input string s1. It is used to track the current position in s1 as we iterate through it using an index (i). Every time we move to the next character in s1, we also increment re, so that it always points to the same character as s1[i].

When a character from s1 is found in s2, re is returned. This ensures the function returns a pointer to the matching character in s1, which is the correct behavior for a strpbrk-like function.